Base | Representation |
---|---|
bin | 10100000010110011110… |
… | …011111001111100000111 |
3 | 11212200022210220001000112 |
4 | 110002303303321330013 |
5 | 140031412000404142 |
6 | 2532434404303235 |
7 | 201341261025563 |
oct | 24026363717407 |
9 | 4780283801015 |
10 | 1377406263047 |
11 | 491177a21311 |
12 | 1a2b4a6a1b1b |
13 | 9cb72a6cc59 |
14 | 4a949a726a3 |
15 | 25c6984e382 |
hex | 140b3cf9f07 |
1377406263047 has 2 divisors, whose sum is σ = 1377406263048. Its totient is φ = 1377406263046.
The previous prime is 1377406263029. The next prime is 1377406263049. The reversal of 1377406263047 is 7403626047731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1377406263047 - 26 = 1377406262983 is a prime.
It is a super-2 number, since 2×13774062630472 (a number of 25 digits) contains 22 as substring.
Together with 1377406263049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1377406262986 and 1377406263004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1377406263049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688703131523 + 688703131524.
It is an arithmetic number, because the mean of its divisors is an integer number (688703131524).
Almost surely, 21377406263047 is an apocalyptic number.
1377406263047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1377406263047 is an equidigital number, since it uses as much as digits as its factorization.
1377406263047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3556224, while the sum is 50.
The spelling of 1377406263047 in words is "one trillion, three hundred seventy-seven billion, four hundred six million, two hundred sixty-three thousand, forty-seven".
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