Base | Representation |
---|---|
bin | 10100000011001000100… |
… | …010110110110001011001 |
3 | 11212201020001102202102011 |
4 | 110003020202312301121 |
5 | 140033120023141121 |
6 | 2532533112105521 |
7 | 201353013515644 |
oct | 24031042666131 |
9 | 4781201382364 |
10 | 1377754115161 |
11 | 4913363097a6 |
12 | 1a30270952a1 |
13 | 9cbc9b535c8 |
14 | 4a97dd40a5b |
15 | 25c8a1617e1 |
hex | 140c88b6c59 |
1377754115161 has 2 divisors, whose sum is σ = 1377754115162. Its totient is φ = 1377754115160.
The previous prime is 1377754115147. The next prime is 1377754115203. The reversal of 1377754115161 is 1615114577731.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1154421313600 + 223332801561 = 1074440^2 + 472581^2 .
It is a cyclic number.
It is not a de Polignac number, because 1377754115161 - 233 = 1369164180569 is a prime.
It is not a weakly prime, because it can be changed into another prime (1377754115261) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688877057580 + 688877057581.
It is an arithmetic number, because the mean of its divisors is an integer number (688877057581).
Almost surely, 21377754115161 is an apocalyptic number.
It is an amenable number.
1377754115161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1377754115161 is an equidigital number, since it uses as much as digits as its factorization.
1377754115161 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 617400, while the sum is 49.
The spelling of 1377754115161 in words is "one trillion, three hundred seventy-seven billion, seven hundred fifty-four million, one hundred fifteen thousand, one hundred sixty-one".
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