137910433301 has 2 divisors, whose sum is σ = 137910433302. Its totient is φ = 137910433300.

The previous prime is 137910433279. The next prime is 137910433303. The reversal of 137910433301 is 103334019731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120165529201 + 17744904100 = 346649^2 + 133210^2 .

It is a cyclic number.

It is not a de Polignac number, because 137910433301 - 2³⁴ = 120730564117 is a prime.

It is a super-2 number, since 2×137910433301² (a number of 23 digits) contains 22 as substring.

Together with 137910433303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137910433303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68955216650 + 68955216651.

It is an arithmetic number, because the mean of its divisors is an integer number (68955216651).

Almost surely, 2^137910433301 is an apocalyptic number.

It is an amenable number.

137910433301 is a deficient number, since it is larger than the sum of its proper divisors (1).

137910433301 is an equidigital number, since it uses as much as digits as its factorization.

137910433301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 35.

The spelling of 137910433301 in words is "one hundred thirty-seven billion, nine hundred ten million, four hundred thirty-three thousand, three hundred one".