Base | Representation |
---|---|
bin | 101001001000011… |
… | …0011010110001101 |
3 | 10120011222012010111 |
4 | 1102100303112031 |
5 | 10311303330313 |
6 | 344541040021 |
7 | 46125652042 |
oct | 12220632615 |
9 | 3504865114 |
10 | 1380136333 |
11 | 649061944 |
12 | 326256011 |
13 | 18cc15424 |
14 | d14211c9 |
15 | 8126e43d |
hex | 5243358d |
1380136333 has 2 divisors, whose sum is σ = 1380136334. Its totient is φ = 1380136332.
The previous prime is 1380136327. The next prime is 1380136339. The reversal of 1380136333 is 3336310831.
It is the 15167-th star number.
It is a balanced prime because it is at equal distance from previous prime (1380136327) and next prime (1380136339).
It can be written as a sum of positive squares in only one way, i.e., 1362938724 + 17197609 = 36918^2 + 4147^2 .
It is a cyclic number.
It is not a de Polignac number, because 1380136333 - 29 = 1380135821 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1380136295 and 1380136304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1380136339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690068166 + 690068167.
It is an arithmetic number, because the mean of its divisors is an integer number (690068167).
Almost surely, 21380136333 is an apocalyptic number.
It is an amenable number.
1380136333 is a deficient number, since it is larger than the sum of its proper divisors (1).
1380136333 is an equidigital number, since it uses as much as digits as its factorization.
1380136333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 31.
The square root of 1380136333 is about 37150.1861771916. The cubic root of 1380136333 is about 1113.3729432304.
The spelling of 1380136333 in words is "one billion, three hundred eighty million, one hundred thirty-six thousand, three hundred thirty-three".
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