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138088074002647 is a prime number
BaseRepresentation
bin11111011001011100100010…
…100110010100000011010111
3200002221002110022011121002011
4133121130202212110003113
5121044413333421041042
61205404441353325051
741041351126326646
oct3731344246240327
9602832408147064
10138088074002647
113aaa990690a1aa
12135a2488706787
135c08859c648c2
1426156d9a2535d
1510e6ec3744a17
hex7d97229940d7

138088074002647 has 2 divisors, whose sum is σ = 138088074002648. Its totient is φ = 138088074002646.

The previous prime is 138088074002537. The next prime is 138088074002677. The reversal of 138088074002647 is 746200470880831.

It is a strong prime.

It is an emirp because it is prime and its reverse (746200470880831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 138088074002647 - 27 = 138088074002519 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 138088074002591 and 138088074002600.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (138088074002677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69044037001323 + 69044037001324.

It is an arithmetic number, because the mean of its divisors is an integer number (69044037001324).

Almost surely, 2138088074002647 is an apocalyptic number.

138088074002647 is a deficient number, since it is larger than the sum of its proper divisors (1).

138088074002647 is an equidigital number, since it uses as much as digits as its factorization.

138088074002647 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14450688, while the sum is 58.

The spelling of 138088074002647 in words is "one hundred thirty-eight trillion, eighty-eight billion, seventy-four million, two thousand, six hundred forty-seven".