Base | Representation |
---|---|
bin | 11111011001011100100010… |
… | …100110010100000011010111 |
3 | 200002221002110022011121002011 |
4 | 133121130202212110003113 |
5 | 121044413333421041042 |
6 | 1205404441353325051 |
7 | 41041351126326646 |
oct | 3731344246240327 |
9 | 602832408147064 |
10 | 138088074002647 |
11 | 3aaa990690a1aa |
12 | 135a2488706787 |
13 | 5c08859c648c2 |
14 | 26156d9a2535d |
15 | 10e6ec3744a17 |
hex | 7d97229940d7 |
138088074002647 has 2 divisors, whose sum is σ = 138088074002648. Its totient is φ = 138088074002646.
The previous prime is 138088074002537. The next prime is 138088074002677. The reversal of 138088074002647 is 746200470880831.
It is a strong prime.
It is an emirp because it is prime and its reverse (746200470880831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 138088074002647 - 27 = 138088074002519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 138088074002591 and 138088074002600.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (138088074002677) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69044037001323 + 69044037001324.
It is an arithmetic number, because the mean of its divisors is an integer number (69044037001324).
Almost surely, 2138088074002647 is an apocalyptic number.
138088074002647 is a deficient number, since it is larger than the sum of its proper divisors (1).
138088074002647 is an equidigital number, since it uses as much as digits as its factorization.
138088074002647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14450688, while the sum is 58.
The spelling of 138088074002647 in words is "one hundred thirty-eight trillion, eighty-eight billion, seventy-four million, two thousand, six hundred forty-seven".
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