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138088074002519 is a prime number
BaseRepresentation
bin11111011001011100100010…
…100110010100000001010111
3200002221002110022011120220102
4133121130202212110001113
5121044413333421040034
61205404441353324315
741041351126326404
oct3731344246240127
9602832408146812
10138088074002519
113aaa990690a0a3
12135a248870669b
135c08859c64824
1426156d9a252ab
1510e6ec374497e
hex7d9722994057

138088074002519 has 2 divisors, whose sum is σ = 138088074002520. Its totient is φ = 138088074002518.

The previous prime is 138088074002407. The next prime is 138088074002521. The reversal of 138088074002519 is 915200470880831.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 138088074002519 - 240 = 136988562374743 is a prime.

It is a super-2 number, since 2×1380880740025192 (a number of 29 digits) contains 22 as substring.

Together with 138088074002521, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (138088074007519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69044037001259 + 69044037001260.

It is an arithmetic number, because the mean of its divisors is an integer number (69044037001260).

Almost surely, 2138088074002519 is an apocalyptic number.

138088074002519 is a deficient number, since it is larger than the sum of its proper divisors (1).

138088074002519 is an equidigital number, since it uses as much as digits as its factorization.

138088074002519 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3870720, while the sum is 56.

The spelling of 138088074002519 in words is "one hundred thirty-eight trillion, eighty-eight billion, seventy-four million, two thousand, five hundred nineteen".