13824660119 has 2 divisors, whose sum is σ = 13824660120. Its totient is φ = 13824660118.

The previous prime is 13824660043. The next prime is 13824660121. The reversal of 13824660119 is 91106642831.

It is a strong prime.

It is an emirp because it is prime and its reverse (91106642831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13824660119 - 2²⁴ = 13807882903 is a prime.

It is a super-2 number, since 2×13824660119² (a number of 21 digits) contains 22 as substring.

Together with 13824660121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13824660419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6912330059 + 6912330060.

It is an arithmetic number, because the mean of its divisors is an integer number (6912330060).

Almost surely, 2^13824660119 is an apocalyptic number.

13824660119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13824660119 is an equidigital number, since it uses as much as digits as its factorization.

13824660119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 41.

The spelling of 13824660119 in words is "thirteen billion, eight hundred twenty-four million, six hundred sixty thousand, one hundred nineteen".