13825007506157 has 2 divisors, whose sum is σ = 13825007506158. Its totient is φ = 13825007506156.

The previous prime is 13825007506151. The next prime is 13825007506159. The reversal of 13825007506157 is 75160570052831.

13825007506157 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8739053403721 + 5085954102436 = 2956189^2 + 2255206^2 .

It is an emirp because it is prime and its reverse (75160570052831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13825007506157 - 2³² = 13820712538861 is a prime.

It is a super-2 number, since 2×13825007506157² (a number of 27 digits) contains 22 as substring.

Together with 13825007506159, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13825007506151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6912503753078 + 6912503753079.

It is an arithmetic number, because the mean of its divisors is an integer number (6912503753079).

Almost surely, 2^{13825007506157} is an apocalyptic number.

It is an amenable number.

13825007506157 is a deficient number, since it is larger than the sum of its proper divisors (1).

13825007506157 is an equidigital number, since it uses as much as digits as its factorization.

13825007506157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1764000, while the sum is 50.

Adding to 13825007506157 its reverse (75160570052831), we get a palindrome (88985577558988).

The spelling of 13825007506157 in words is "thirteen trillion, eight hundred twenty-five billion, seven million, five hundred six thousand, one hundred fifty-seven".