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138340231215007 is a prime number
BaseRepresentation
bin11111011101000111011000…
…010101101111011110011111
3200010211012022120110012020111
4133131013120111233132133
5121113031243142340012
61210120342545430451
741065515615300403
oct3735073025573637
9603735276405214
10138340231215007
1140096842aa8a88
121362331b63b427
135c26573c237c3
1426239bab37103
1510ed830b27ba7
hex7dd1d856f79f

138340231215007 has 2 divisors, whose sum is σ = 138340231215008. Its totient is φ = 138340231215006.

The previous prime is 138340231214909. The next prime is 138340231215013. The reversal of 138340231215007 is 700512132043831.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 138340231215007 - 27 = 138340231214879 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (138340231215097) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69170115607503 + 69170115607504.

It is an arithmetic number, because the mean of its divisors is an integer number (69170115607504).

Almost surely, 2138340231215007 is an apocalyptic number.

138340231215007 is a deficient number, since it is larger than the sum of its proper divisors (1).

138340231215007 is an equidigital number, since it uses as much as digits as its factorization.

138340231215007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

Adding to 138340231215007 its reverse (700512132043831), we get a palindrome (838852363258838).

The spelling of 138340231215007 in words is "one hundred thirty-eight trillion, three hundred forty billion, two hundred thirty-one million, two hundred fifteen thousand, seven".