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13835147 is a prime number
BaseRepresentation
bin110100110001…
…101110001011
3222000220020212
4310301232023
512020211042
61212311335
7225411464
oct64615613
928026225
1013835147
11789a607
12477254b
132b353a1
141ba1d6b
151334482
hexd31b8b

13835147 has 2 divisors, whose sum is σ = 13835148. Its totient is φ = 13835146.

The previous prime is 13835141. The next prime is 13835149. The reversal of 13835147 is 74153831.

It is a strong prime.

It is an emirp because it is prime and its reverse (74153831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13835147 - 218 = 13573003 is a prime.

It is a super-2 number, since 2×138351472 = 382822585023218, which contains 22 as substring.

Together with 13835149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13835141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6917573 + 6917574.

It is an arithmetic number, because the mean of its divisors is an integer number (6917574).

Almost surely, 213835147 is an apocalyptic number.

13835147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13835147 is an equidigital number, since it uses as much as digits as its factorization.

13835147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10080, while the sum is 32.

The square root of 13835147 is about 3719.5627431191. The cubic root of 13835147 is about 240.0644907709.

Adding to 13835147 its reverse (74153831), we get a palindrome (87988978).

The spelling of 13835147 in words is "thirteen million, eight hundred thirty-five thousand, one hundred forty-seven".