Base | Representation |
---|---|
bin | 1000000100110111001… |
… | …0100010101010101101 |
3 | 111021010022101220220121 |
4 | 2001031302202222231 |
5 | 4233121434021201 |
6 | 143423234244541 |
7 | 13011130644355 |
oct | 2011562425255 |
9 | 437108356817 |
10 | 138744048301 |
11 | 53928442031 |
12 | 22a81126751 |
13 | 1011160a401 |
14 | 6a028d5b65 |
15 | 39208329a1 |
hex | 204dca2aad |
138744048301 has 4 divisors (see below), whose sum is σ = 141095642400. Its totient is φ = 136392454204.
The previous prime is 138744048281. The next prime is 138744048323. The reversal of 138744048301 is 103840447831.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 138744048301 - 225 = 138710493869 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (138744048361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1175796961 + ... + 1175797078.
It is an arithmetic number, because the mean of its divisors is an integer number (35273910600).
Almost surely, 2138744048301 is an apocalyptic number.
It is an amenable number.
138744048301 is a deficient number, since it is larger than the sum of its proper divisors (2351594099).
138744048301 is an equidigital number, since it uses as much as digits as its factorization.
138744048301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2351594098.
The product of its (nonzero) digits is 258048, while the sum is 43.
The spelling of 138744048301 in words is "one hundred thirty-eight billion, seven hundred forty-four million, forty-eight thousand, three hundred one".
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