Base | Representation |
---|---|
bin | 1000000101001010011… |
… | …1011001010101000111 |
3 | 111021022221202022222112 |
4 | 2001102213121111013 |
5 | 4233303200400201 |
6 | 143435245451235 |
7 | 13013133064631 |
oct | 2012247312507 |
9 | 437287668875 |
10 | 138825012551 |
11 | 5396a111735 |
12 | 22aa4270b1b |
13 | 10125317654 |
14 | 6a0d56da51 |
15 | 39279c70bb |
hex | 20529d9547 |
138825012551 has 2 divisors, whose sum is σ = 138825012552. Its totient is φ = 138825012550.
The previous prime is 138825012493. The next prime is 138825012577. The reversal of 138825012551 is 155210528831.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-138825012551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 138825012499 and 138825012508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (138825018551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69412506275 + 69412506276.
It is an arithmetic number, because the mean of its divisors is an integer number (69412506276).
Almost surely, 2138825012551 is an apocalyptic number.
138825012551 is a deficient number, since it is larger than the sum of its proper divisors (1).
138825012551 is an equidigital number, since it uses as much as digits as its factorization.
138825012551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96000, while the sum is 41.
The spelling of 138825012551 in words is "one hundred thirty-eight billion, eight hundred twenty-five million, twelve thousand, five hundred fifty-one".
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