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1388404488197 is a prime number
BaseRepresentation
bin10100001101000011010…
…110110011100000000101
311220201201021222202121202
4110031003112303200011
5140221423022110242
62541454010352245
7202210646300126
oct24150326634005
94821637882552
101388404488197
11495901157691
121a50b9a2b685
13a0c064c579c
144b2b060004d
15261b018c932
hex143435b3805

1388404488197 has 2 divisors, whose sum is σ = 1388404488198. Its totient is φ = 1388404488196.

The previous prime is 1388404488139. The next prime is 1388404488239. The reversal of 1388404488197 is 7918844048831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 994565403841 + 393839084356 = 997279^2 + 627566^2 .

It is a cyclic number.

It is not a de Polignac number, because 1388404488197 - 228 = 1388136052741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1388404484197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 694202244098 + 694202244099.

It is an arithmetic number, because the mean of its divisors is an integer number (694202244099).

Almost surely, 21388404488197 is an apocalyptic number.

It is an amenable number.

1388404488197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1388404488197 is an equidigital number, since it uses as much as digits as its factorization.

1388404488197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 49545216, while the sum is 65.

The spelling of 1388404488197 in words is "one trillion, three hundred eighty-eight billion, four hundred four million, four hundred eighty-eight thousand, one hundred ninety-seven".