Base | Representation |
---|---|
bin | 1100101000100100101111… |
… | …1001010000001110101111 |
3 | 1211011222121102220001210012 |
4 | 3022021023321100032233 |
5 | 3310043133032111101 |
6 | 45313310020403435 |
7 | 2632414552561166 |
oct | 312111371201657 |
9 | 54158542801705 |
10 | 13891197535151 |
11 | 4476250958452 |
12 | 1684259b4657b |
13 | 799c1b897631 |
14 | 3604a23363dd |
15 | 19151e005bbb |
hex | ca24be503af |
13891197535151 has 2 divisors, whose sum is σ = 13891197535152. Its totient is φ = 13891197535150.
The previous prime is 13891197535133. The next prime is 13891197535169. The reversal of 13891197535151 is 15153579119831.
13891197535151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (13891197535133) and next prime (13891197535169).
It is a cyclic number.
It is not a de Polignac number, because 13891197535151 - 26 = 13891197535087 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13891197535051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6945598767575 + 6945598767576.
It is an arithmetic number, because the mean of its divisors is an integer number (6945598767576).
Almost surely, 213891197535151 is an apocalyptic number.
13891197535151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13891197535151 is an equidigital number, since it uses as much as digits as its factorization.
13891197535151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5103000, while the sum is 59.
The spelling of 13891197535151 in words is "thirteen trillion, eight hundred ninety-one billion, one hundred ninety-seven million, five hundred thirty-five thousand, one hundred fifty-one".
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