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1389495841541 is a prime number
BaseRepresentation
bin10100001110000100011…
…001111111001100000101
311220211112100120020221222
4110032010121333030011
5140231141413412131
62542154154050125
7202250000531243
oct24160431771405
94824470506858
101389495841541
114963111a65a5
121a5363419945
13a104b6398b2
144b37552b793
1526225db687b
hex1438467f305

1389495841541 has 2 divisors, whose sum is σ = 1389495841542. Its totient is φ = 1389495841540.

The previous prime is 1389495841537. The next prime is 1389495841543. The reversal of 1389495841541 is 1451485949831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1113561004516 + 275934837025 = 1055254^2 + 525295^2 .

It is an emirp because it is prime and its reverse (1451485949831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1389495841541 - 22 = 1389495841537 is a prime.

Together with 1389495841543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1389495841543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 694747920770 + 694747920771.

It is an arithmetic number, because the mean of its divisors is an integer number (694747920771).

Almost surely, 21389495841541 is an apocalyptic number.

It is an amenable number.

1389495841541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1389495841541 is an equidigital number, since it uses as much as digits as its factorization.

1389495841541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24883200, while the sum is 62.

The spelling of 1389495841541 in words is "one trillion, three hundred eighty-nine billion, four hundred ninety-five million, eight hundred forty-one thousand, five hundred forty-one".