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139066412117 is a prime number
BaseRepresentation
bin1000000110000100000…
…0010000110001010101
3111021221202222200221012
42001201000100301111
54234302000141432
6143515231502005
713022123666513
oct2014100206125
9437852880835
10139066412117
1153a83400806
1222b51087905
1310163338529
146a3364b4b3
15393dcaccb2
hex2061010c55

139066412117 has 2 divisors, whose sum is σ = 139066412118. Its totient is φ = 139066412116.

The previous prime is 139066412081. The next prime is 139066412129. The reversal of 139066412117 is 711214660931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103226621521 + 35839790596 = 321289^2 + 189314^2 .

It is a cyclic number.

It is not a de Polignac number, because 139066412117 - 26 = 139066412053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (139066412137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69533206058 + 69533206059.

It is an arithmetic number, because the mean of its divisors is an integer number (69533206059).

Almost surely, 2139066412117 is an apocalyptic number.

It is an amenable number.

139066412117 is a deficient number, since it is larger than the sum of its proper divisors (1).

139066412117 is an equidigital number, since it uses as much as digits as its factorization.

139066412117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 41.

The spelling of 139066412117 in words is "one hundred thirty-nine billion, sixty-six million, four hundred twelve thousand, one hundred seventeen".