139128254001 has 81 divisors (see below), whose sum is σ = 225176015883. Its totient is φ = 82716258240.

The previous prime is 139128253967. The next prime is 139128254003. The reversal of 139128254001 is 100452821931.

The square root of 139128254001 is 372999.

It is a perfect power (a square), and thus also a powerful number.

139128254001 is a `hidden beast` number, since 1 + 3 + 91 + 28 + 2 + 540 + 0 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 26715575601 + 112412678400 = 163449^2 + 335280^2 .

It is not a de Polignac number, because 139128254001 - 2¹¹ = 139128251953 is a prime.

It is a super-2 number, since 2×139128254001² (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (139128254003) by changing a digit.

It is a polite number, since it can be written in 80 ways as a sum of consecutive naturals, for example, 1095498000 + ... + 1095498126.

Almost surely, 2^139128254001 is an apocalyptic number.

139128254001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

139128254001 is the 372999-th square number.

139128254001 is the 186500-th centered octagonal number.

It is an amenable number.

139128254001 is a deficient number, since it is larger than the sum of its proper divisors (86047761882).

139128254001 is an equidigital number, since it uses as much as digits as its factorization.

139128254001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 460 (or 230 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 36.

Multiplying 139128254001 by its sum of digits (36), we get a square (5008617144036 = 2237994²).

It can be divided in two parts, 139128 and 254001, that added together give a square (393129 = 627²).

The spelling of 139128254001 in words is "one hundred thirty-nine billion, one hundred twenty-eight million, two hundred fifty-four thousand, one".