Base | Representation |
---|---|
bin | 1100101011100101011001… |
… | …1001111011100110101101 |
3 | 1211100221002121120022202221 |
4 | 3022321112121323212231 |
5 | 3311420041322344013 |
6 | 45353141440515341 |
7 | 2636225252062000 |
oct | 312712631734655 |
9 | 54327077508687 |
10 | 13942913481133 |
11 | 449617a19507a |
12 | 169229161bb51 |
13 | 7a1a70ca79c0 |
14 | 362baa8dd537 |
15 | 192a4934e08d |
hex | cae5667b9ad |
13942913481133 has 16 divisors (see below), whose sum is σ = 17510723372800. Its totient is φ = 11031755717808.
The previous prime is 13942913481121. The next prime is 13942913481149. The reversal of 13942913481133 is 33118431924931.
It is a happy number.
It is not a de Polignac number, because 13942913481133 - 213 = 13942913472941 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13942913481173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1563452985 + ... + 1563461902.
It is an arithmetic number, because the mean of its divisors is an integer number (1094420210800).
Almost surely, 213942913481133 is an apocalyptic number.
13942913481133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13942913481133 is a deficient number, since it is larger than the sum of its proper divisors (3567809891667).
13942913481133 is an equidigital number, since it uses as much as digits as its factorization.
13942913481133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3126914921 (or 3126914907 counting only the distinct ones).
The product of its digits is 1679616, while the sum is 52.
The spelling of 13942913481133 in words is "thirteen trillion, nine hundred forty-two billion, nine hundred thirteen million, four hundred eighty-one thousand, one hundred thirty-three".
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