Base | Representation |
---|---|
bin | 101001100100110… |
… | …0100101010111111 |
3 | 10121012222021112022 |
4 | 1103021210222333 |
5 | 10324111042211 |
6 | 350232030355 |
7 | 46366314062 |
oct | 12311445277 |
9 | 3535867468 |
10 | 1395018431 |
11 | 6564a6aa4 |
12 | 32b2323bb |
13 | 1930261c1 |
14 | d33b68d9 |
15 | 8270dbdb |
hex | 53264abf |
1395018431 has 2 divisors, whose sum is σ = 1395018432. Its totient is φ = 1395018430.
The previous prime is 1395018371. The next prime is 1395018451. The reversal of 1395018431 is 1348105931.
It is a strong prime.
It is an emirp because it is prime and its reverse (1348105931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1395018431 - 214 = 1395002047 is a prime.
It is a super-2 number, since 2×13950184312 = 3892152845659403522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1395018391 and 1395018400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1395018451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 697509215 + 697509216.
It is an arithmetic number, because the mean of its divisors is an integer number (697509216).
Almost surely, 21395018431 is an apocalyptic number.
1395018431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1395018431 is an equidigital number, since it uses as much as digits as its factorization.
1395018431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 35.
The square root of 1395018431 is about 37349.9455287421. The cubic root of 1395018431 is about 1117.3605018163.
The spelling of 1395018431 in words is "one billion, three hundred ninety-five million, eighteen thousand, four hundred thirty-one".
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