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139511768413 is a prime number
BaseRepresentation
bin1000000111101110001…
…1001010010101011101
3111100002211000010220211
42001323203022111131
54241210003042123
6144031341212421
713036142315413
oct2017343122535
9440084003824
10139511768413
1154191835566
1223056261111
131020469a674
146a7685b2b3
153967e3040d
hex207b8ca55d

139511768413 has 2 divisors, whose sum is σ = 139511768414. Its totient is φ = 139511768412.

The previous prime is 139511768381. The next prime is 139511768471. The reversal of 139511768413 is 314867115931.

It is a happy number.

139511768413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 137479291524 + 2032476889 = 370782^2 + 45083^2 .

It is a cyclic number.

It is not a de Polignac number, because 139511768413 - 25 = 139511768381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (139511768113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69755884206 + 69755884207.

It is an arithmetic number, because the mean of its divisors is an integer number (69755884207).

Almost surely, 2139511768413 is an apocalyptic number.

It is an amenable number.

139511768413 is a deficient number, since it is larger than the sum of its proper divisors (1).

139511768413 is an equidigital number, since it uses as much as digits as its factorization.

139511768413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 544320, while the sum is 49.

The spelling of 139511768413 in words is "one hundred thirty-nine billion, five hundred eleven million, seven hundred sixty-eight thousand, four hundred thirteen".