Base | Representation |
---|---|
bin | 1000000111111000100… |
… | …0010100001110001111 |
3 | 111100012211110201110212 |
4 | 2001332020110032033 |
5 | 4241302044001141 |
6 | 144035525153035 |
7 | 13040206313633 |
oct | 2017610241617 |
9 | 440184421425 |
10 | 139555062671 |
11 | 54204216142 |
12 | 2306885b77b |
13 | 1021064877b |
14 | 6a7c4cadc3 |
15 | 396bb332eb |
hex | 207e21438f |
139555062671 has 2 divisors, whose sum is σ = 139555062672. Its totient is φ = 139555062670.
The previous prime is 139555062649. The next prime is 139555062679. The reversal of 139555062671 is 176260555931.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-139555062671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (139555062679) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69777531335 + 69777531336.
It is an arithmetic number, because the mean of its divisors is an integer number (69777531336).
Almost surely, 2139555062671 is an apocalyptic number.
139555062671 is a deficient number, since it is larger than the sum of its proper divisors (1).
139555062671 is an equidigital number, since it uses as much as digits as its factorization.
139555062671 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1701000, while the sum is 50.
The spelling of 139555062671 in words is "one hundred thirty-nine billion, five hundred fifty-five million, sixty-two thousand, six hundred seventy-one".
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