13956332625070 has 32 divisors (see below), whose sum is σ = 27407746764000. Its totient is φ = 5074551431040.

The previous prime is 13956332625061. The next prime is 13956332625071. The reversal of 13956332625070 is 7052623365931.

It is a super-3 number, since 3×13956332625070³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13956332624999 and 13956332625017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13956332625071) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4809945 + ... + 7144804.

It is an arithmetic number, because the mean of its divisors is an integer number (856492086375).

Almost surely, 2^{13956332625070} is an apocalyptic number.

13956332625070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13956332625070 is a deficient number, since it is larger than the sum of its proper divisors (13451414138930).

13956332625070 is a wasteful number, since it uses less digits than its factorization.

13956332625070 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11965380.

The product of its (nonzero) digits is 6123600, while the sum is 52.

The spelling of 13956332625070 in words is "thirteen trillion, nine hundred fifty-six billion, three hundred thirty-two million, six hundred twenty-five thousand, seventy".