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13970057053 is a prime number
BaseRepresentation
bin11010000001010111…
…00010011101011101
31100001121010102120111
431000223202131131
5212102313311203
610230122450021
71003122345211
oct150053423535
940047112514
1013970057053
115a198076a7
12285a663911
131418356b64
14967520941
1556b6bb26d
hex340ae275d

13970057053 has 2 divisors, whose sum is σ = 13970057054. Its totient is φ = 13970057052.

The previous prime is 13970057039. The next prime is 13970057077. The reversal of 13970057053 is 35075007931.

13970057053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9161744089 + 4808312964 = 95717^2 + 69342^2 .

It is a cyclic number.

It is not a de Polignac number, because 13970057053 - 229 = 13433186141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13970056997 and 13970057015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13970057083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6985028526 + 6985028527.

It is an arithmetic number, because the mean of its divisors is an integer number (6985028527).

Almost surely, 213970057053 is an apocalyptic number.

It is an amenable number.

13970057053 is a deficient number, since it is larger than the sum of its proper divisors (1).

13970057053 is an equidigital number, since it uses as much as digits as its factorization.

13970057053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 99225, while the sum is 40.

The spelling of 13970057053 in words is "thirteen billion, nine hundred seventy million, fifty-seven thousand, fifty-three".