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13999423 is a prime number
BaseRepresentation
bin110101011001…
…110100111111
3222100020121011
4311121310333
512040440143
61220020051
7226664434
oct65316477
928306534
1013999423
1179a1a79
124831627
132b920a9
141c05b8b
151367e9d
hexd59d3f

13999423 has 2 divisors, whose sum is σ = 13999424. Its totient is φ = 13999422.

The previous prime is 13999421. The next prime is 13999441. The reversal of 13999423 is 32499931.

13999423 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13999423 - 21 = 13999421 is a prime.

Together with 13999421, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13999421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6999711 + 6999712.

It is an arithmetic number, because the mean of its divisors is an integer number (6999712).

Almost surely, 213999423 is an apocalyptic number.

13999423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13999423 is an equidigital number, since it uses as much as digits as its factorization.

13999423 is an evil number, because the sum of its binary digits is even.

The product of its digits is 52488, while the sum is 40.

The square root of 13999423 is about 3741.5802811112. The cubic root of 13999423 is about 241.0109152956.

The spelling of 13999423 in words is "thirteen million, nine hundred ninety-nine thousand, four hundred twenty-three".