1400113310331 has 4 divisors (see below), whose sum is σ = 1866817747112. Its totient is φ = 933408873552.

The previous prime is 1400113310317. The next prime is 1400113310333. The reversal of 1400113310331 is 1330133110041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1400113310331 - 2¹¹ = 1400113308283 is a prime.

It is a super-3 number, since 3×1400113310331³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400113310298 and 1400113310307.

It is not an unprimeable number, because it can be changed into a prime (1400113310333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233352218386 + ... + 233352218391.

It is an arithmetic number, because the mean of its divisors is an integer number (466704436778).

Almost surely, 2^{1400113310331} is an apocalyptic number.

1400113310331 is a deficient number, since it is larger than the sum of its proper divisors (466704436781).

1400113310331 is an equidigital number, since it uses as much as digits as its factorization.

1400113310331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 466704436780.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 1400113310331 its reverse (1330133110041), we get a palindrome (2730246420372).

The spelling of 1400113310331 in words is "one trillion, four hundred billion, one hundred thirteen million, three hundred ten thousand, three hundred thirty-one".