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140011543120303 is a prime number
BaseRepresentation
bin11111110101011011111010…
…010010101100100110101111
3200100201222021011122210211101
4133311123322102230212233
5121322422120014322203
61213440225344103531
741330333363141041
oct3765337222544657
9610658234583741
10140011543120303
114068061aaa8398
1213853212604ba7
136018055009cba
142680848379a91
15112c04cab041d
hex7f56fa4ac9af

140011543120303 has 2 divisors, whose sum is σ = 140011543120304. Its totient is φ = 140011543120302.

The previous prime is 140011543120279. The next prime is 140011543120331. The reversal of 140011543120303 is 303021345110041.

It is an a-pointer prime, because the next prime (140011543120331) can be obtained adding 140011543120303 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140011543120303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140011543120003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70005771560151 + 70005771560152.

It is an arithmetic number, because the mean of its divisors is an integer number (70005771560152).

Almost surely, 2140011543120303 is an apocalyptic number.

140011543120303 is a deficient number, since it is larger than the sum of its proper divisors (1).

140011543120303 is an equidigital number, since it uses as much as digits as its factorization.

140011543120303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 140011543120303 its reverse (303021345110041), we get a palindrome (443032888230344).

The spelling of 140011543120303 in words is "one hundred forty trillion, eleven billion, five hundred forty-three million, one hundred twenty thousand, three hundred three".