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140012000000063 is a prime number
BaseRepresentation
bin11111110101011100010101…
…100001100011100000111111
3200100202000110000100201000222
4133311130111201203200333
5121322424034000000223
61213440342544411555
741330350611433022
oct3765342541434077
9610660400321028
10140012000000063
1140680834992974
121385331b616bbb
1360180c8875259
14268088cd091b9
15112c077c5c0c8
hex7f571586383f

140012000000063 has 2 divisors, whose sum is σ = 140012000000064. Its totient is φ = 140012000000062.

The previous prime is 140012000000003. The next prime is 140012000000083. The reversal of 140012000000063 is 360000000210041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140012000000063 - 224 = 140011983222847 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140011999999978 and 140012000000050.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140012000000003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006000000031 + 70006000000032.

It is an arithmetic number, because the mean of its divisors is an integer number (70006000000032).

Almost surely, 2140012000000063 is an apocalyptic number.

140012000000063 is a deficient number, since it is larger than the sum of its proper divisors (1).

140012000000063 is an equidigital number, since it uses as much as digits as its factorization.

140012000000063 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The spelling of 140012000000063 in words is "one hundred forty trillion, twelve billion, sixty-three", and thus it is an aban number.