Base | Representation |
---|---|
bin | 1100101110111110100010… |
… | …0011010110110110010011 |
3 | 1211120111112200221021211220 |
4 | 3023233220203112312103 |
5 | 3313343424200003103 |
6 | 45440021255140123 |
7 | 2643360534240030 |
oct | 313575043266623 |
9 | 54514480837756 |
10 | 14001200000403 |
11 | 450896a431760 |
12 | 16a1639674643 |
13 | 7a73cc748665 |
14 | 36593999c387 |
15 | 19430b438c53 |
hex | cbbe88d6d93 |
14001200000403 has 32 divisors (see below), whose sum is σ = 23769928949760. Its totient is φ = 7118598502560.
The previous prime is 14001200000327. The next prime is 14001200000441. The reversal of 14001200000403 is 30400000210041.
It is not a de Polignac number, because 14001200000403 - 214 = 14001199984019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14001200000443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 644789733 + ... + 644811446.
It is an arithmetic number, because the mean of its divisors is an integer number (742810279680).
Almost surely, 214001200000403 is an apocalyptic number.
14001200000403 is a deficient number, since it is larger than the sum of its proper divisors (9768728949357).
14001200000403 is a wasteful number, since it uses less digits than its factorization.
14001200000403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1289601247.
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 14001200000403 its reverse (30400000210041), we get a palindrome (44401200210444).
The spelling of 14001200000403 in words is "fourteen trillion, one billion, two hundred million, four hundred three", and thus it is an aban number.
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