14001200000441 has 2 divisors, whose sum is σ = 14001200000442. Its totient is φ = 14001200000440.

The previous prime is 14001200000327. The next prime is 14001200000443. The reversal of 14001200000441 is 14400000210041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13884782560441 + 116417440000 = 3726229^2 + 341200^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14001200000441 is a prime.

Together with 14001200000443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14001200000443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000600000220 + 7000600000221.

It is an arithmetic number, because the mean of its divisors is an integer number (7000600000221).

Almost surely, 2^{14001200000441} is an apocalyptic number.

It is an amenable number.

14001200000441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14001200000441 is an equidigital number, since it uses as much as digits as its factorization.

14001200000441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 14001200000441 its reverse (14400000210041), we get a palindrome (28401200210482).

The spelling of 14001200000441 in words is "fourteen trillion, one billion, two hundred million, four hundred forty-one", and thus it is an aban number.