14001200000327 has 2 divisors, whose sum is σ = 14001200000328. Its totient is φ = 14001200000326.

The previous prime is 14001200000273. The next prime is 14001200000441. The reversal of 14001200000327 is 72300000210041.

Together with previous prime (14001200000273) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (72300000210041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14001200000327 - 2²² = 14001195806023 is a prime.

It is a super-3 number, since 3×14001200000327³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14001200000299 and 14001200000308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14001200002327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000600000163 + 7000600000164.

It is an arithmetic number, because the mean of its divisors is an integer number (7000600000164).

Almost surely, 2^{14001200000327} is an apocalyptic number.

14001200000327 is a deficient number, since it is larger than the sum of its proper divisors (1).

14001200000327 is an equidigital number, since it uses as much as digits as its factorization.

14001200000327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 20.

Adding to 14001200000327 its reverse (72300000210041), we get a palindrome (86301200210368).

The spelling of 14001200000327 in words is "fourteen trillion, one billion, two hundred million, three hundred twenty-seven", and thus it is an aban number.