Base | Representation |
---|---|
bin | 11111110101011100010101… |
… | …100010101111100000000110 |
3 | 200100202000110000221111222100 |
4 | 133311130111202233200012 |
5 | 121322424034034430202 |
6 | 1213440342555212530 |
7 | 41330350614200310 |
oct | 3765342542574006 |
9 | 610660400844870 |
10 | 140012000311302 |
11 | 40680835085799 |
12 | 1385331b747146 |
13 | 60180c8953b12 |
14 | 268088cd8a7b0 |
15 | 112c077cbe41c |
hex | 7f57158af806 |
140012000311302 has 48 divisors (see below), whose sum is σ = 346758705296640. Its totient is φ = 39996237478896.
The previous prime is 140012000311231. The next prime is 140012000311331. The reversal of 140012000311302 is 203113000210041.
140012000311302 is a `hidden beast` number, since 1 + 40 + 0 + 12 + 0 + 0 + 0 + 311 + 302 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 99173802 + ... + 100575677.
It is an arithmetic number, because the mean of its divisors is an integer number (7224139693680).
Almost surely, 2140012000311302 is an apocalyptic number.
140012000311302 is an abundant number, since it is smaller than the sum of its proper divisors (206746704985338).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140012000311302 is a wasteful number, since it uses less digits than its factorization.
140012000311302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 199755057 (or 199755054 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 140012000311302 its reverse (203113000210041), we get a palindrome (343125000521343).
The spelling of 140012000311302 in words is "one hundred forty trillion, twelve billion, three hundred eleven thousand, three hundred two".
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