14001201201401 has 4 divisors (see below), whose sum is σ = 14238509696400. Its totient is φ = 13763892706404.

The previous prime is 14001201201349. The next prime is 14001201201511. The reversal of 14001201201401 is 10410210210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001201201401 - 2¹⁰ = 14001201200377 is a prime.

It is a super-2 number, since 2×14001201201401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14001201201401.

It is not an unprimeable number, because it can be changed into a prime (14001201204401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118654247411 + ... + 118654247528.

It is an arithmetic number, because the mean of its divisors is an integer number (3559627424100).

Almost surely, 2^{14001201201401} is an apocalyptic number.

It is an amenable number.

14001201201401 is a deficient number, since it is larger than the sum of its proper divisors (237308494999).

14001201201401 is an equidigital number, since it uses as much as digits as its factorization.

14001201201401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237308494998.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 14001201201401 its reverse (10410210210041), we get a palindrome (24411411411442).

The spelling of 14001201201401 in words is "fourteen trillion, one billion, two hundred one million, two hundred one thousand, four hundred one".