Base | Representation |
---|---|
bin | 10100010111111101110… |
… | …011100110000011001111 |
3 | 11221211221221120001211211 |
4 | 110113331303212003033 |
5 | 140414422332011142 |
6 | 2551112444555251 |
7 | 203104225105231 |
oct | 24277563460317 |
9 | 4854857501754 |
10 | 1400122532047 |
11 | 49a874739448 |
12 | 1a742a252b27 |
13 | a2053109445 |
14 | 4baa29c4251 |
15 | 26648cb5917 |
hex | 145fdce60cf |
1400122532047 has 2 divisors, whose sum is σ = 1400122532048. Its totient is φ = 1400122532046.
The previous prime is 1400122531987. The next prime is 1400122532059. The reversal of 1400122532047 is 7402352210041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1400122532047 - 219 = 1400122007759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400102532047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700061266023 + 700061266024.
It is an arithmetic number, because the mean of its divisors is an integer number (700061266024).
Almost surely, 21400122532047 is an apocalyptic number.
1400122532047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400122532047 is an equidigital number, since it uses as much as digits as its factorization.
1400122532047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 1400122532047 its reverse (7402352210041), we get a palindrome (8802474742088).
The spelling of 1400122532047 in words is "one trillion, four hundred billion, one hundred twenty-two million, five hundred thirty-two thousand, forty-seven".
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