Base | Representation |
---|---|
bin | 10100010111111101111… |
… | …010011001011110011111 |
3 | 11221211222001220200100112 |
4 | 110113331322121132133 |
5 | 140414423311044201 |
6 | 2551112551120235 |
7 | 203104246214033 |
oct | 24277572313637 |
9 | 4854861820315 |
10 | 1400124315551 |
11 | 49a875747415 |
12 | 1a742a97307b |
13 | a20535b2180 |
14 | 4baa2d2a1c3 |
15 | 266490190bb |
hex | 145fde9979f |
1400124315551 has 4 divisors (see below), whose sum is σ = 1507826185992. Its totient is φ = 1292422445112.
The previous prime is 1400124315533. The next prime is 1400124315581. The reversal of 1400124315551 is 1555134210041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1400124315551 - 222 = 1400120121247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1400124315581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53850935201 + ... + 53850935226.
It is an arithmetic number, because the mean of its divisors is an integer number (376956546498).
Almost surely, 21400124315551 is an apocalyptic number.
1400124315551 is a deficient number, since it is larger than the sum of its proper divisors (107701870441).
1400124315551 is a wasteful number, since it uses less digits than its factorization.
1400124315551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107701870440.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 1400124315551 its reverse (1555134210041), we get a palindrome (2955258525592).
The spelling of 1400124315551 in words is "one trillion, four hundred billion, one hundred twenty-four million, three hundred fifteen thousand, five hundred fifty-one".
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