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1400124315551 = 13107701870427
BaseRepresentation
bin10100010111111101111…
…010011001011110011111
311221211222001220200100112
4110113331322121132133
5140414423311044201
62551112551120235
7203104246214033
oct24277572313637
94854861820315
101400124315551
1149a875747415
121a742a97307b
13a20535b2180
144baa2d2a1c3
15266490190bb
hex145fde9979f

1400124315551 has 4 divisors (see below), whose sum is σ = 1507826185992. Its totient is φ = 1292422445112.

The previous prime is 1400124315533. The next prime is 1400124315581. The reversal of 1400124315551 is 1555134210041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1400124315551 - 222 = 1400120121247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400124315581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53850935201 + ... + 53850935226.

It is an arithmetic number, because the mean of its divisors is an integer number (376956546498).

Almost surely, 21400124315551 is an apocalyptic number.

1400124315551 is a deficient number, since it is larger than the sum of its proper divisors (107701870441).

1400124315551 is a wasteful number, since it uses less digits than its factorization.

1400124315551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107701870440.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 1400124315551 its reverse (1555134210041), we get a palindrome (2955258525592).

The spelling of 1400124315551 in words is "one trillion, four hundred billion, one hundred twenty-four million, three hundred fifteen thousand, five hundred fifty-one".

Divisors: 1 13 107701870427 1400124315551