Base | Representation |
---|---|
bin | 1100101110111110111010… |
… | …0101000111010011001111 |
3 | 1211120111210202012220202112 |
4 | 3023233232211013103033 |
5 | 3313344131041434203 |
6 | 45440035310414235 |
7 | 2643363202622633 |
oct | 313575645072317 |
9 | 54514722186675 |
10 | 14001301124303 |
11 | 4508a11520629 |
12 | 16a166750137b |
13 | 7a741769389c |
14 | 3659491a2dc3 |
15 | 1943152616d8 |
hex | cbbee9474cf |
14001301124303 has 4 divisors (see below), whose sum is σ = 14001702193248. Its totient is φ = 14000900055360.
The previous prime is 14001301124299. The next prime is 14001301124339. The reversal of 14001301124303 is 30342110310041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14001301124303 - 22 = 14001301124299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14001301124203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200482103 + ... + 200551928.
It is an arithmetic number, because the mean of its divisors is an integer number (3500425548312).
Almost surely, 214001301124303 is an apocalyptic number.
14001301124303 is a deficient number, since it is larger than the sum of its proper divisors (401068945).
14001301124303 is an equidigital number, since it uses as much as digits as its factorization.
14001301124303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 401068944.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 14001301124303 its reverse (30342110310041), we get a palindrome (44343411434344).
The spelling of 14001301124303 in words is "fourteen trillion, one billion, three hundred one million, one hundred twenty-four thousand, three hundred three".
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