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14001351523 is a prime number
BaseRepresentation
bin11010000101000101…
…11010101101100011
31100010210000100111221
431002202322231203
5212133321222043
610233201315511
71003652344555
oct150242725543
940123010457
1014001351523
115a354416a5
122869035b97
1314219930b3
1496b7494d5
1556e2ed8ed
hex3428bab63

14001351523 has 2 divisors, whose sum is σ = 14001351524. Its totient is φ = 14001351522.

The previous prime is 14001351509. The next prime is 14001351547. The reversal of 14001351523 is 32515310041.

It is a happy number.

14001351523 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (32515310041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14001351523 - 25 = 14001351491 is a prime.

It is a super-2 number, since 2×140013515232 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14001351323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000675761 + 7000675762.

It is an arithmetic number, because the mean of its divisors is an integer number (7000675762).

Almost surely, 214001351523 is an apocalyptic number.

14001351523 is a deficient number, since it is larger than the sum of its proper divisors (1).

14001351523 is an equidigital number, since it uses as much as digits as its factorization.

14001351523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 14001351523 its reverse (32515310041), we get a palindrome (46516661564).

The spelling of 14001351523 in words is "fourteen billion, one million, three hundred fifty-one thousand, five hundred twenty-three".