1400135340031 has 4 divisors (see below), whose sum is σ = 1400137706752. Its totient is φ = 1400132973312.

The previous prime is 1400135339969. The next prime is 1400135340139. The reversal of 1400135340031 is 1300435310041.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1400135340031 - 2¹¹ = 1400135337983 is a prime.

It is a super-2 number, since 2×1400135340031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400135339978 and 1400135340005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400135340931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570175 + ... + 1767871.

It is an arithmetic number, because the mean of its divisors is an integer number (350034426688).

Almost surely, 2^{1400135340031} is an apocalyptic number.

1400135340031 is a deficient number, since it is larger than the sum of its proper divisors (2366721).

1400135340031 is a wasteful number, since it uses less digits than its factorization.

1400135340031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2366720.

The product of its (nonzero) digits is 2160, while the sum is 25.

The spelling of 1400135340031 in words is "one trillion, four hundred billion, one hundred thirty-five million, three hundred forty thousand, thirty-one".