1400142113 has 4 divisors (see below), whose sum is σ = 1400393748. Its totient is φ = 1399890480.

The previous prime is 1400142103. The next prime is 1400142119. The reversal of 1400142113 is 3112410041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 180176929 + 1219965184 = 13423^2 + 34928^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400142113 - 2⁴ = 1400142097 is a prime.

It is a super-2 number, since 2×1400142113² = 3920795873192209538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400142091 and 1400142100.

It is not an unprimeable number, because it can be changed into a prime (1400142119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117278 + ... + 128663.

It is an arithmetic number, because the mean of its divisors is an integer number (350098437).

Almost surely, 2^1400142113 is an apocalyptic number.

It is an amenable number.

1400142113 is a deficient number, since it is larger than the sum of its proper divisors (251635).

1400142113 is an equidigital number, since it uses as much as digits as its factorization.

1400142113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 251634.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1400142113 is about 37418.4728843923. The cubic root of 1400142113 is about 1118.7267932392.

Adding to 1400142113 its reverse (3112410041), we get a palindrome (4512552154).

The spelling of 1400142113 in words is "one billion, four hundred million, one hundred forty-two thousand, one hundred thirteen".