Base | Representation |
---|---|
bin | 1100101111000001100001… |
… | …0100100010000000010111 |
3 | 1211120120121112221122021201 |
4 | 3023300120110202000113 |
5 | 3313402044330422221 |
6 | 45440233004253331 |
7 | 2643416435216152 |
oct | 313603024420027 |
9 | 54516545848251 |
10 | 14002001420311 |
11 | 4509240852363 |
12 | 16a1821b41247 |
13 | 7a74c97a7918 |
14 | 3659b41b6c99 |
15 | 194356991891 |
hex | cbc18522017 |
14002001420311 has 2 divisors, whose sum is σ = 14002001420312. Its totient is φ = 14002001420310.
The previous prime is 14002001420233. The next prime is 14002001420321. The reversal of 14002001420311 is 11302410020041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14002001420311 - 217 = 14002001289239 is a prime.
It is a super-2 number, since 2×140020014203112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14002001420321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001000710155 + 7001000710156.
It is an arithmetic number, because the mean of its divisors is an integer number (7001000710156).
Almost surely, 214002001420311 is an apocalyptic number.
14002001420311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14002001420311 is an equidigital number, since it uses as much as digits as its factorization.
14002001420311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 14002001420311 its reverse (11302410020041), we get a palindrome (25304411440352).
The spelling of 14002001420311 in words is "fourteen trillion, two billion, one million, four hundred twenty thousand, three hundred eleven".
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