Base | Representation |
---|---|
bin | 10100011000000010011… |
… | …111010100011100011011 |
3 | 11221212011102101220002222 |
4 | 110120002133110130123 |
5 | 140420102440300011 |
6 | 2551124333014255 |
7 | 203106201000365 |
oct | 24300237243433 |
9 | 4855142356088 |
10 | 1400201103131 |
11 | 49a905024026 |
12 | 1a745062438b |
13 | a20664892cc |
14 | 4baad1d7d35 |
15 | 26650b35ddb |
hex | 146027d471b |
1400201103131 has 2 divisors, whose sum is σ = 1400201103132. Its totient is φ = 1400201103130.
The previous prime is 1400201103083. The next prime is 1400201103137. The reversal of 1400201103131 is 1313011020041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1400201103131 - 214 = 1400201086747 is a prime.
It is a super-2 number, since 2×14002011031312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1400201103137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700100551565 + 700100551566.
It is an arithmetic number, because the mean of its divisors is an integer number (700100551566).
Almost surely, 21400201103131 is an apocalyptic number.
1400201103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400201103131 is an equidigital number, since it uses as much as digits as its factorization.
1400201103131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1400201103131 its reverse (1313011020041), we get a palindrome (2713212123172).
The spelling of 1400201103131 in words is "one trillion, four hundred billion, two hundred one million, one hundred three thousand, one hundred thirty-one".
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