14002020013 has 2 divisors, whose sum is σ = 14002020014. Its totient is φ = 14002020012.

The previous prime is 14002019897. The next prime is 14002020031. The reversal of 14002020013 is 31002020041.

Together with next prime (14002020031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12534593764 + 1467426249 = 111958^2 + 38307^2 .

It is a cyclic number.

It is not a de Polignac number, because 14002020013 - 2²¹ = 13999922861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14002019975 and 14002020002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14002020073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001010006 + 7001010007.

It is an arithmetic number, because the mean of its divisors is an integer number (7001010007).

Almost surely, 2^14002020013 is an apocalyptic number.

It is an amenable number.

14002020013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14002020013 is an equidigital number, since it uses as much as digits as its factorization.

14002020013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 14002020013 its reverse (31002020041), we get a palindrome (45004040054).

The spelling of 14002020013 in words is "fourteen billion, two million, twenty thousand, thirteen".