Base | Representation |
---|---|
bin | 10100011000000011001… |
… | …001110011011010000011 |
3 | 11221212012012100201000201 |
4 | 110120003021303122003 |
5 | 140420113313140003 |
6 | 2551125411430031 |
7 | 203106364443403 |
oct | 24300311633203 |
9 | 4855165321021 |
10 | 1400212240003 |
11 | 49a910340355 |
12 | 1a74542b5317 |
13 | a2068888485 |
14 | 4bab0896803 |
15 | 26651ad5b1d |
hex | 14603273683 |
1400212240003 has 2 divisors, whose sum is σ = 1400212240004. Its totient is φ = 1400212240002.
The previous prime is 1400212240001. The next prime is 1400212240027. The reversal of 1400212240003 is 3000422120041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1400212240003 - 21 = 1400212240001 is a prime.
Together with 1400212240001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1400212240001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700106120001 + 700106120002.
It is an arithmetic number, because the mean of its divisors is an integer number (700106120002).
Almost surely, 21400212240003 is an apocalyptic number.
1400212240003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400212240003 is an equidigital number, since it uses as much as digits as its factorization.
1400212240003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 1400212240003 its reverse (3000422120041), we get a palindrome (4400634360044).
The spelling of 1400212240003 in words is "one trillion, four hundred billion, two hundred twelve million, two hundred forty thousand, three".
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