140021311342133 has 8 divisors (see below), whose sum is σ = 150879800401176. Its totient is φ = 129175339276800.

The previous prime is 140021311342061. The next prime is 140021311342141. The reversal of 140021311342133 is 331243113120041.

It can be written as a sum of positive squares in 4 ways, for example, as 26113142450404 + 113908168891729 = 5110102^2 + 10672777^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140021311342133 - 2¹⁸ = 140021311079989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140021311342096 and 140021311342105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140021311042133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3129225188 + ... + 3129269933.

It is an arithmetic number, because the mean of its divisors is an integer number (18859975050147).

Almost surely, 2^{140021311342133} is an apocalyptic number.

140021311342133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

140021311342133 is a deficient number, since it is larger than the sum of its proper divisors (10858489059043).

140021311342133 is a wasteful number, since it uses less digits than its factorization.

140021311342133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6258496855.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 140021311342133 its reverse (331243113120041), we get a palindrome (471264424462174).

The spelling of 140021311342133 in words is "one hundred forty trillion, twenty-one billion, three hundred eleven million, three hundred forty-two thousand, one hundred thirty-three".