Base | Representation |
---|---|
bin | 10100011000000011001… |
… | …110001110111010001111 |
3 | 11221212012021112200221011 |
4 | 110120003032032322033 |
5 | 140420114112314411 |
6 | 2551125452350051 |
7 | 203106410351041 |
oct | 24300316167217 |
9 | 4855167480834 |
10 | 1400213401231 |
11 | 49a910a63847 |
12 | 1a7454775327 |
13 | a2068ba3ba8 |
14 | 4bab0ab9a91 |
15 | 26651c64c21 |
hex | 1460338ee8f |
1400213401231 has 2 divisors, whose sum is σ = 1400213401232. Its totient is φ = 1400213401230.
The previous prime is 1400213401219. The next prime is 1400213401253. The reversal of 1400213401231 is 1321043120041.
It is an a-pointer prime, because the next prime (1400213401253) can be obtained adding 1400213401231 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1400213401231 is a prime.
It is a super-2 number, since 2×14002134012312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400213401291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700106700615 + 700106700616.
It is an arithmetic number, because the mean of its divisors is an integer number (700106700616).
Almost surely, 21400213401231 is an apocalyptic number.
1400213401231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400213401231 is an equidigital number, since it uses as much as digits as its factorization.
1400213401231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1400213401231 its reverse (1321043120041), we get a palindrome (2721256521272).
The spelling of 1400213401231 in words is "one trillion, four hundred billion, two hundred thirteen million, four hundred one thousand, two hundred thirty-one".
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