Base | Representation |
---|---|
bin | 1000001001100111111… |
… | …0011011101101011111 |
3 | 111101102101112110222212 |
4 | 2002121332123231133 |
5 | 4243231142441301 |
6 | 144154134231035 |
7 | 13054611231215 |
oct | 2023176335537 |
9 | 441371473885 |
10 | 140022233951 |
11 | 5442399a906 |
12 | 231791b547b |
13 | 10286378192 |
14 | 6ac4578cb5 |
15 | 3997b644bb |
hex | 2099f9bb5f |
140022233951 has 2 divisors, whose sum is σ = 140022233952. Its totient is φ = 140022233950.
The previous prime is 140022233947. The next prime is 140022234007. The reversal of 140022233951 is 159332220041.
It is a weak prime.
It is an emirp because it is prime and its reverse (159332220041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140022233951 - 22 = 140022233947 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140022233941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011116975 + 70011116976.
It is an arithmetic number, because the mean of its divisors is an integer number (70011116976).
Almost surely, 2140022233951 is an apocalyptic number.
140022233951 is a deficient number, since it is larger than the sum of its proper divisors (1).
140022233951 is an equidigital number, since it uses as much as digits as its factorization.
140022233951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 140022233951 its reverse (159332220041), we get a palindrome (299354453992).
The spelling of 140022233951 in words is "one hundred forty billion, twenty-two million, two hundred thirty-three thousand, nine hundred fifty-one".
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