Base | Representation |
---|---|
bin | 11111110101100110101011… |
… | …001101010001101101001111 |
3 | 200100210002002200020011011210 |
4 | 133311212223031101231033 |
5 | 121323114302401414411 |
6 | 1213445420305545503 |
7 | 41331222660203013 |
oct | 3765465315215517 |
9 | 610702080204153 |
10 | 140023101201231 |
11 | 40685511262696 |
12 | 138554b9345293 |
13 | 6019177744041 |
14 | 2681223400543 |
15 | 112c4c763bca6 |
hex | 7f59ab351b4f |
140023101201231 has 4 divisors (see below), whose sum is σ = 186697468268312. Its totient is φ = 93348734134152.
The previous prime is 140023101201187. The next prime is 140023101201241. The reversal of 140023101201231 is 132102101320041.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 140023101201231 - 213 = 140023101193039 is a prime.
It is a super-2 number, since 2×1400231012012312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 140023101201198 and 140023101201207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140023101201241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23337183533536 + ... + 23337183533541.
It is an arithmetic number, because the mean of its divisors is an integer number (46674367067078).
Almost surely, 2140023101201231 is an apocalyptic number.
140023101201231 is a deficient number, since it is larger than the sum of its proper divisors (46674367067081).
140023101201231 is an equidigital number, since it uses as much as digits as its factorization.
140023101201231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46674367067080.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 140023101201231 its reverse (132102101320041), we get a palindrome (272125202521272).
The spelling of 140023101201231 in words is "one hundred forty trillion, twenty-three billion, one hundred one million, two hundred one thousand, two hundred thirty-one".
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