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140023402011221 is a prime number
BaseRepresentation
bin11111110101100110111101…
…001000110001101001010101
3200100210002212122020212220112
4133311212331020301221111
5121323120411403324341
61213445510213212405
741331233302065041
oct3765467510615125
9610702778225815
10140023402011221
114068565603a693
1213855582031105
1360191c4b66711
142681251345021
15112c4e3c5aaeb
hex7f59bd231a55

140023402011221 has 2 divisors, whose sum is σ = 140023402011222. Its totient is φ = 140023402011220.

The previous prime is 140023402011193. The next prime is 140023402011263. The reversal of 140023402011221 is 122110204320041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98202748672900 + 41820653338321 = 9909730^2 + 6466889^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140023402011221 is a prime.

It is a super-2 number, since 2×1400234020112212 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140023402016221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011701005610 + 70011701005611.

It is an arithmetic number, because the mean of its divisors is an integer number (70011701005611).

Almost surely, 2140023402011221 is an apocalyptic number.

It is an amenable number.

140023402011221 is a deficient number, since it is larger than the sum of its proper divisors (1).

140023402011221 is an equidigital number, since it uses as much as digits as its factorization.

140023402011221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 140023402011221 its reverse (122110204320041), we get a palindrome (262133606331262).

The spelling of 140023402011221 in words is "one hundred forty trillion, twenty-three billion, four hundred two million, eleven thousand, two hundred twenty-one".