140024114013301 has 8 divisors (see below), whose sum is σ = 164352628031360. Its totient is φ = 116776867285008.

The previous prime is 140024114013281. The next prime is 140024114013307. The reversal of 140024114013301 is 103310411420041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 140024114013301 - 2⁵ = 140024114013269 is a prime.

It is a super-3 number, since 3×140024114013301³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140024114013307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 270316822161 + ... + 270316822678.

It is an arithmetic number, because the mean of its divisors is an integer number (20544078503920).

Almost surely, 2^{140024114013301} is an apocalyptic number.

It is an amenable number.

140024114013301 is a deficient number, since it is larger than the sum of its proper divisors (24328514018059).

140024114013301 is an equidigital number, since it uses as much as digits as its factorization.

140024114013301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 540633644883.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140024114013301 its reverse (103310411420041), we get a palindrome (243334525433342).

The spelling of 140024114013301 in words is "one hundred forty trillion, twenty-four billion, one hundred fourteen million, thirteen thousand, three hundred one".