Base | Representation |
---|---|
bin | 11010000101010011… |
… | …00110110101011011 |
3 | 1100010220022102222210 |
4 | 31002221212311123 |
5 | 212134243330430 |
6 | 10233303050203 |
7 | 1004003300226 |
oct | 150251466533 |
9 | 40126272883 |
10 | 14003105115 |
11 | 5a3642a14a |
12 | 2869740963 |
13 | 142215831c |
14 | 96ba845bd |
15 | 56e5482b0 |
hex | 342a66d5b |
14003105115 has 16 divisors (see below), whose sum is σ = 22476557088. Its totient is φ = 7444459776.
The previous prime is 14003105113. The next prime is 14003105119. The reversal of 14003105115 is 51150130041.
It is a happy number.
It is not a de Polignac number, because 14003105115 - 21 = 14003105113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14003105091 and 14003105100.
It is not an unprimeable number, because it can be changed into a prime (14003105113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1486584 + ... + 1495973.
It is an arithmetic number, because the mean of its divisors is an integer number (1404784818).
Almost surely, 214003105115 is an apocalyptic number.
14003105115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14003105115 is a deficient number, since it is larger than the sum of its proper divisors (8473451973).
14003105115 is a wasteful number, since it uses less digits than its factorization.
14003105115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2982878.
The product of its (nonzero) digits is 300, while the sum is 21.
Adding to 14003105115 its reverse (51150130041), we get a palindrome (65153235156).
The spelling of 14003105115 in words is "fourteen billion, three million, one hundred five thousand, one hundred fifteen".
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