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51150130041 = 383205422209
BaseRepresentation
bin101111101000110010…
…010000101101111001
311220000201222211102210
4233220302100231321
51314223413130131
635255324445333
73460355634363
oct575062205571
9156021884383
1051150130041
111a768a0784a
129ab60a9849
134a9212304a
14269339bd33
1514e582e146
hexbe8c90b79

51150130041 has 8 divisors (see below), whose sum is σ = 69021862560. Its totient is φ = 33689242112.

The previous prime is 51150130037. The next prime is 51150130117. The reversal of 51150130041 is 14003105115.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51150130041 - 22 = 51150130037 is a prime.

It is a super-2 number, since 2×511501300412 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (51150130021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102710856 + ... + 102711353.

It is an arithmetic number, because the mean of its divisors is an integer number (8627732820).

Almost surely, 251150130041 is an apocalyptic number.

It is an amenable number.

51150130041 is a deficient number, since it is larger than the sum of its proper divisors (17871732519).

51150130041 is a wasteful number, since it uses less digits than its factorization.

51150130041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 205422295.

The product of its (nonzero) digits is 300, while the sum is 21.

Adding to 51150130041 its reverse (14003105115), we get a palindrome (65153235156).

The spelling of 51150130041 in words is "fifty-one billion, one hundred fifty million, one hundred thirty thousand, forty-one".

Divisors: 1 3 83 249 205422209 616266627 17050043347 51150130041